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Rewrite the expression

 

\(\ln (a+b) + 4 \ln (a-b) - 3 \ln c\)

 

as a single logarithm \(\ln A.\) . Then the function A=

 Jun 7, 2018

Best Answer 

 #1
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Ln A = Ln {[(a+b)(a-b)^4]/(c^3)}

 

A = [(a+b)(a-b)^4]/(c^3)

 Jun 7, 2018
 #1
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Best Answer

Ln A = Ln {[(a+b)(a-b)^4]/(c^3)}

 

A = [(a+b)(a-b)^4]/(c^3)

Guest Jun 7, 2018

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