Rhombus ABCD has perimeter of 148, and one of its diagonals has length of 24 . What is the area of ABCD
+36916 A rhombus has 4 equal sides..... 148/4 = 37 side length
The diaonals of a rhombus bisect each other (at right angles)....we can find the 1/2 length of the other diagonal
since 1/2 of the diagonal given and the other 1/2 form a right triangle with one side of the rhombus (37) as a hypotenuse
24/2 = 12 12^2 + x^2 = 37^2 x = 35 so the other diagonal is 2*35= 70
Area Rhombus = diagonal1 x diagonal2 / 2 = 24 x 70/2 = 840 sq units
+36916 A rhombus has 4 equal sides..... 148/4 = 37 side length
The diaonals of a rhombus bisect each other (at right angles)....we can find the 1/2 length of the other diagonal
since 1/2 of the diagonal given and the other 1/2 form a right triangle with one side of the rhombus (37) as a hypotenuse
24/2 = 12 12^2 + x^2 = 37^2 x = 35 so the other diagonal is 2*35= 70
Area Rhombus = diagonal1 x diagonal2 / 2 = 24 x 70/2 = 840 sq units
