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Given: Parallelogram ABCD is a rhombus. Side BC = 5 cm and segment AO = 3.9 cm.

 

 

1. What is the area of ABCD?

4 * (3.9cm) * (3.129cm) / 2

2 * (3.9cm) * (3.129cm)

= 24.4cm^2

 

2. What is the length of diagonal BD?

BD = 0B + 0D = 3.129cm + 3.129cm

=6.26cm

 

3. What is the measure of angle d1°?

4. What is the tangent ratio of angle c2 ?

Guest Nov 28, 2018
 #1
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The diagonals of a rhombus intersect at right angles

So....the tangent ratio of c1 is

 

OD / OC   =  sqrt ( 5^2 - 3.9^2) / 3.9   =  sqrt (9.79) / 3.9

 

 

d1 can be found thusly

 

tan d1   = 3.9 / sqrt (9.79)        take the arctan

 

artan [ 3.9 / sqrt (9.79) ] = d1 ≈ 51.26°

 

 

cool cool cool

CPhill  Nov 28, 2018

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