Parallelogram ABCD is a rhombus with EBC = 36. What is DAE?
Since DB is a transversla cutting parallels AB and Dc, then angle CBE = angle ADE = 36°
And angle AED = 90°
So...in triangle ADE, angle DAE = 180 - angle AED - angle ADE =
180 - 90 - 36 =
90 - 36 =
54°