A rhombus with area 840 has a diagonal of length 42. What is its side length?
+178 I believe there is insufficent evidence to solve this problem; I think the diagonals must be perpendicular.
Assuming they are, then the length of the other diagonal is \(\frac{840*2}{42} = 40\)
Then, the length of each side is going to be \(\sqrt{20^2+21^2}=29.\)
