A rhombus with area 840 has a diagonal of length 42. What is its side length?

Guest May 19, 2021

#1**+1 **

I believe there is insufficent evidence to solve this problem; I think the diagonals must be perpendicular.

Assuming they are, then the length of the other diagonal is \(\frac{840*2}{42} = 40\)

Then, the length of each side is going to be \(\sqrt{20^2+21^2}=29.\)

ilovepizza547 May 19, 2021