Rhombus ABCD has perimeter 148, and one of its diagonals has length 28. what is the area of ABCD?
+36916 Each side of the rhombus is 148 / 4 = 37
The diagonals of a rhombus intersect at right angles
the other diagonal could be found via pythag theorem
28/2 = 14
37^2 = 14^2 + x^2
x = 34.249
area = 4 * 1/2 * 14 * 34.249 = 958.97 units2
