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Right  △ABC has its right angle at C, BC=4 , and AC=8 .

What is the value of the trigonometric ratio?

 

SinA = ?

 Mar 18, 2020

Best Answer 

 #1
avatar+23553 
+2

First find the length of the hypotenuse using pythagorean theorem       c2  = a2+b2

 

then draw the triangle

 

sin a  =  opposite / hypotenuse        where ' opposite'   is the side leg that is opposite angle A

 Mar 18, 2020
 #1
avatar+23553 
+2
Best Answer

First find the length of the hypotenuse using pythagorean theorem       c2  = a2+b2

 

then draw the triangle

 

sin a  =  opposite / hypotenuse        where ' opposite'   is the side leg that is opposite angle A

ElectricPavlov Mar 18, 2020
 #2
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0

I can't tell if sin a = √5/5 or just √5

Guest Mar 19, 2020
 #3
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0

is either one of those answers right? please help

Guest Mar 19, 2020
 #4
avatar+111360 
+1

sin A  =   BC / BA

 

We  need  to  find BA.....this is  = √[8^2 + 4^2 ]  = √80  =  4√5

 

So

 

sin A  =  4 / [ 4√5]  =   1  / √5

 

Rationalizing the denominator we  have   sin A  =   √5 / 5

 

 

 

 

cool cool cool

 Mar 19, 2020

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