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In the diagram below, we have AB = 24, angle ADB = 90, and angles A and C are acute. If sin A = 1/2 and sin C = 1/4, then what is BC?

 

 Dec 6, 2020
 #1
avatar+114221 
+1

sin A  =   BD/BA   =1/2

 

BD / BA   =1/2

 

BD  =(1/2) BA

 

BD  = (1/2)24  =   12

 

sin C  =  BD / BC  = 1/4

 

BD/ BC   =1/4

 

BC /BD  =  4

 

BC = 12 (4)   =  48

 

cool cool cool

 Dec 6, 2020
 #2
avatar+846 
+2

In the diagram below, we have AB = 24, angle ADB = 90, and angles A and C are acute. If sin A = 1/2 and sin C = 1/4, then what is BC?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

BC = [24*sin(A)] / sin(C)  ==> BC = (24 * 1/2) / 1/4 = 48

 Dec 6, 2020

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