Right △EFG has its right angle at F, EG=10 , and FG=4 . What is the value of the trigonometric ratio of an angle of the triangle?
Tan G=
cos E=
sec G=
The other, leg, EF = sqrt (EG^2 - FG^2 ) = sqrt (10^2 - 4^2) = sqrt (100 - 16) = sqrt (84) = 2sqrt (21)
Tan G = EF / FG = 2sqrt (21) 4 = sqrt (21) / 2
Cos E = EF / EG = 2sqrt (21) / 10 = sqrt (21) / 5
Sec G = EG / FG = 10 / 4 = 5/2
