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Right △EFG has its right angle at F, EG=10 , and FG=4 . What is the value of the trigonometric ratio of an angle of the triangle?

 

Tan G=

 

cos E=

 

sec G=

 Feb 12, 2020
 #1
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The other, leg, EF =  sqrt (EG^2 - FG^2 ) =  sqrt (10^2 - 4^2)  = sqrt (100 - 16)  = sqrt (84)  = 2sqrt (21)

 

Tan G  =   EF /  FG  =      2sqrt (21)   4  =    sqrt (21) / 2

 

Cos E  =  EF / EG  =  2sqrt (21)  / 10   =  sqrt (21)  / 5

 

Sec G =  EG / FG =  10 / 4  =   5/2 

 

 

cool cool cool

 Feb 12, 2020

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