My thinking:
1)
(a) (i) 9996 (\(11424*\frac{7}{8}\))
(ii) It is then a consequential error, if you have (i) wrong,
then you would also have (ii) wrong.
21420 (\(11424+9996\))
(b) (i) rounded to 50.61% (\(\frac{42320}{100}\)) is 423.2 and (\(\frac{21420}{423\frac{1}{5}}\))
From here I have to go.
Straight