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a) i) 13 056
ii) 24 480
b)42.2%
c) i) 156
ii) 52
thx

 Oct 20, 2021
 #1
avatar+390 
+1

My thinking:

 

1)  

 

  (a)   (i) 9996 (\(11424*\frac{7}{8}\))

         (ii) It is then a consequential error, if you have (i) wrong,

              then you would also have (ii) wrong.

              21420 (\(11424+9996\))

  (b)   (i) rounded to 50.61% (\(\frac{42320}{100}\)) is 423.2 and (\(\frac{21420}{423\frac{1}{5}}\))

  From here I have to go.

 

Straight

 Oct 20, 2021
 #2
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0

how-
for (i) it is \((7/8)x=11424 \)

Guest Oct 20, 2021
 #3
avatar+390 
0

Hello Guest,

 

no, think again about what you are saying.

You will get the answer.

 

Straight

 Oct 21, 2021

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