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Given a right triangle HTO, with angle TOH is equal to 60 degrees and side TO is equal to 5, what is the length of side HT?

 Oct 21, 2015
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I'm NOT familiar with the description of triangle in terms of letters. I assume the the given side "TO" is the Adjacent side.If that is so, then we have:

Cos(60)=5/Hypotenuse

.5=5/H

H=5/.5

H=10, then we have:

10^2=5^2 + (HT)^2

HT^2=100 - 25=75

HT=Sqrt(75)

HT=8.66. If "TO" is the Hypotenuse, then:

HT=4.33

 Oct 21, 2015

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