c = \(\sqrt{3^2 + 4^2} = 5\)
This means b = \(\sqrt{(a + 3)^2 - c^2}\)
but b also equals = \(\sqrt{a^2 + 4^2}\)
We can put these two into an equation:
\(\sqrt{(a + 3)^2 - c^2} = \sqrt{a^2 + 4^2}\)
\(a^2 + 6a + 9 - c^2 = a^2 + 16\)
\(6a - c^2 = 7\)
and since c = 5,
\(6a - 25 = 7\)
\(6a = 32\)
\(a = 5\frac{1}{3}\)