I have a right triangle that has an adjacent side measured at .992 meters, an opposite side of .213 meters. What is the length of the hypotenuse?
Use Pythagoras: h = √(0.992^2 + 0.213^2) metres
$${\mathtt{h}} = {\sqrt{{{\mathtt{0.992}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{0.213}}}^{{\mathtt{2}}}}} \Rightarrow {\mathtt{h}} = {\mathtt{1.014\: \!609\: \!777\: \!205\: \!01}}$$
h ≈ 1.015 metres
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