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I have a right triangle that has an adjacent side measured at .992 meters, an opposite side of .213 meters. What is the length of the hypotenuse?

 May 2, 2015

Best Answer 

 #1
avatar+33661 
+10

Use Pythagoras:  h = √(0.992^2 + 0.213^2) metres

 

$${\mathtt{h}} = {\sqrt{{{\mathtt{0.992}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{0.213}}}^{{\mathtt{2}}}}} \Rightarrow {\mathtt{h}} = {\mathtt{1.014\: \!609\: \!777\: \!205\: \!01}}$$

 

h ≈ 1.015 metres

.

 May 2, 2015
 #1
avatar+33661 
+10
Best Answer

Use Pythagoras:  h = √(0.992^2 + 0.213^2) metres

 

$${\mathtt{h}} = {\sqrt{{{\mathtt{0.992}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{0.213}}}^{{\mathtt{2}}}}} \Rightarrow {\mathtt{h}} = {\mathtt{1.014\: \!609\: \!777\: \!205\: \!01}}$$

 

h ≈ 1.015 metres

.

Alan May 2, 2015

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