In the diagram below, we have $AB = 24$, $\angle ADB =90^\circ$, and angles $A$ and $C$ are acute. If $\sin A = \frac23$ and $\sin C = \frac34$, then what is $BC$?
If Sin(A) = 2/3, then:
2/3 =BD / 24
BD =16
If sin(C) = 3/4, then:
3/4 = 16 / BC
BC =64 / 3 =21 1/3
