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In right triangle $ABC$, we have $AB = 10$, $BC = 24$, and $\angle ABC = 90^\circ$. If $M$ is on $\overline{AC}$ such that $\overline{BM}$ is an angle bisector of $\triangle ABC$, then what is $\cos \angle ABM$?

 Apr 19, 2021
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                                       707,106,781

cos∠ABM = cos∠(45º) = --------------------   laugh

                                     1,000,000,000

 Apr 19, 2021

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