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In right triangle $BCD$ with $\angle D = 90^\circ$, we have $BC = 9$ and $BD = 4$. Find $\sin B$.

 Apr 19, 2021
 #1
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sin B = 4/9.

 Apr 19, 2021
 #2
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sinB = CD/BC

 

sinB = √65 / 9

Guest Apr 19, 2021

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