+0

# Right-Triangle Trigonometry

0
76
2
+500

In right triangle $BCD$ with $\angle D = 90^\circ$, we have $BC = 9$ and $BD = 4$. Find $\sin B$.

Apr 19, 2021

#1
0

sin B = 4/9.

Apr 19, 2021
#2
0

sinB = CD/BC

sinB = √65 / 9

Guest Apr 19, 2021