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 \(ABCD\)is a regular tetrahedron (right pyramid whose faces are all equilateral triangles). If \(M\) is the midpoint of line \(\overline{CD}\), then what is \(\cos \angle ABM\)?

 Feb 18, 2023
 #1
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cos ABM = 2/3.

 Feb 18, 2023
 #2
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Nope! :), it was sqrt3 /3!

Guest Feb 18, 2023

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