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$ABCDEFGH$  shown below is a cube. Find $\sin \angle HAC$..

 Nov 24, 2018
edited by Guest  Nov 24, 2018
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Let the side of the cube be, S

 

HA  = S√2

AC = S√2

CH = S√2

 

So.....HAC forms an equilateral triangle.....and each angle = 60°

 

So....the sin 60°   = sin HAC =   √3 / 2 

 

 

cool cool cool

 Nov 25, 2018

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