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In \(\triangle XYZ\), we have \(\angle X = 90^\circ\) and \(\tan Z = 3\). What is \(\cos Z\)?

 Mar 14, 2021
 #1
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arctan (3) = 71.565

 

cos (71.565) =.31623

 

Here is the exact method:

 

tan = opp / adj      pick opp = 3   then    adj = 1    hypotenuse = sqrt (10)     via Pythagorean theorem

                               cos = adj/hypot = 1/sqrt(10)

                                                         = sqrt 10 / 10  

 Mar 14, 2021
 #2
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Thank you!

Guest Mar 14, 2021

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