In \(\triangle XYZ\), we have \(\angle X = 90^\circ\) and \(\tan Z = 3\). What is \(\cos Z\)?
+37146 arctan (3) = 71.565
cos (71.565) =.31623
Here is the exact method:
tan = opp / adj pick opp = 3 then adj = 1 hypotenuse = sqrt (10) via Pythagorean theorem
cos = adj/hypot = 1/sqrt(10)
= sqrt 10 / 10
