Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 11and DC = 4, what is the length of BC in simplest radical form?
AB = 10since ABC is a 6-8-10 triangle. 6^2 = 10x
3.6 = x
AD AB
---- = ------
AB AC
Given a right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 11and DC = 4, what is the length of BC in simplest radical form?
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AC = 11 DC = 4 BC => x
x/11 = 4/x
x2 = 44 x = √44
BC = 2√11
+237 
