The side lengths of a right triangle measure x, x + y, and x + 2y units where 0 < y < x. What is the value of y/x? Express your answer as a common fraction

Guest Mar 17, 2021

#1**0 **

(x)^2 + (x+y)^2 = (x + 2y)^2 (this is the pythagreon theorum)

x^2 + x^2 + y^2 + 2xy = x^2 + 4y^2 + 4xy

2x^2 + y^2 + 2xy = x^2 + 4y^2 + 4xy

x^2 = 3y^2 + 2xy

So we're looking for xy, and we could solve for it, but let's just say x = 1 for simplicity.

1^2 = 3*y^2 + 2(1)y

1 = 3y^2 + 2y.

y = 1/3.

So y/x = 1/3/1 = 1/3.

I hope this helped. :)))

=^._.^=

catmg Mar 17, 2021