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2sin2x=-radice 3

Guest Feb 16, 2017
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Is this what you mean? 2sin2x=-sqrt(3)???. if so, then:

 

Solve for x:
2 sin(2 x) = -sqrt(3)

Divide both sides by 2:
sin(2 x) = -sqrt(3)/2

Take the inverse sine of both sides:
2 x = (4 π)/3 + 2 π n_1 for n_1 element Z
 or 2 x = (5 π)/3 + 2 π n_2 for n_2 element Z

Divide both sides by 2:
x = (2 π)/3 + π n_1 for n_1 element Z
 or 2 x = (5 π)/3 + 2 π n_2 for n_2 element Z

Divide both sides by 2:
Answer: |
 | x = (2 π)/3 + π n_1 for n_1 element Z
 or x = (5 π)/6 + π n_2 for n_2 element Z

Guest Feb 16, 2017

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