Harry rolls four fair 10-sided dice. What is the probability that exactly three of the dice show a prime number?

Thanks for help.

Guest Dec 27, 2021

#1**+1 **

There are four prime numbers (2, 3, 5, 7) in the first 10 whole numbers.

The probability of rolling a prime is 4/10 and the probability of not rolling a prime is 6/10.

The probability that exactly three of the dice show a prime number is:

_{4}C_{3} · (4/10)^{3} · (6/10)^{1}

geno3141 Dec 27, 2021