$\sqrt{2}$ is the sixth root of what positive whole number?
(21/2)6 = 23 = 8
\(\displaystyle 2^\frac{1}{2}=y^{\frac{1}{6}}\\~\\ \displaystyle \left(2^\frac{1}{2}\right)^6=\left(y^{\frac{1}{6}}\right)^6\\~\\ \displaystyle 2^3=y\\~\\ y=8\)
