3x^2 + 4x + 12 = 2x^2 + 3x + 11
x^2 + x + 1 = 0
We're going to use vieta's formula. (https://artofproblemsolving.com/wiki/index.php/Vieta%27s_Formulas)
r^2 + s^2 = (r+s)^2 - 2rs
r^2 + s^2 = (-1)^2 - 2(1)
r^2 + s^2 = 1 - 2
-1
I hope this helped. :))
=^._.^=