If the roots of the quadratic equation 1/2*x^2 + 99x + c are x = -99 - sqrt(7801) and -99 + sqrt(7801), then what is the value of c?
What is the value of c?
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\(0.5x^2 + 99x + c=0\)
\(x = {-99 \pm \sqrt{99^2-4\cdot 0.5\cdot c} \over 2\cdot 0.5}\)
\(99^2-4\cdot 0.5\cdot c=7801\\c=-\dfrac{7801-99^2}{2}\)
\(c=1000\)
The value of c is 1000.
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