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If the roots of the quadratic equation 1/2*x^2 + 99x + c are x  = -99 - sqrt(7801) and -99 + sqrt(7801), then what is the value of c?

 
 Oct 10, 2021
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What is the value of c?

 

Hello Guest!

 

\(0.5x^2 + 99x + c=0\)

\(x = {-99 \pm \sqrt{99^2-4\cdot 0.5\cdot c} \over 2\cdot 0.5}\)

\(99^2-4\cdot 0.5\cdot c=7801\\c=-\dfrac{7801-99^2}{2}\)

\(c=1000\)

 

The value of c is 1000.

laugh  !
 

 
 Oct 10, 2021

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