The polynomial p(x) = x^2+ax+b has distinct roots 2a and b. Find a+b.
Set the two givens =
(x-2a)(x-b) = x^2 +ax+b
x^2 -2ax-bx+2ab = x^2+ax+b
-2ax-bx+2ab = ax+b
so -2ax-bx = ax and 2ab = b
-2a-b = a and 2 ab = b
-b = 3a and 2a = 1
-b = 3a and a = 1/2
-b = 3/2
b = -3/2 You can add them together...I hope !
hepl i catn ad them so wht s the anser
-3/2+1/2=-2/2=-1
The answer is -1!
+131 
