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The polynomial p(x) = x^2+ax+b has distinct roots 2a and b. Find a+b.

 Jun 26, 2023
 #2
avatar+131 
+1

Set the two givens =

(x-2a)(x-b) = x^2 +ax+b

x^2 -2ax-bx+2ab = x^2+ax+b

-2ax-bx+2ab = ax+b

 

so    -2ax-bx = ax      and   2ab = b  

        -2a-b = a          and    2 ab = b

         -b = 3a             and   2a = 1

         -b = 3a             and  a = 1/2

        -b = 3/2

         b = -3/2                  You can add them together...I hope !   

 Jun 27, 2023
 #4
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hepl i catn ad them so wht s the anser

Guest Jun 27, 2023
 #5
avatar+131 
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-3/2+1/2=-2/2=-1

 

The answer is -1!

SportzGuy2310  Jun 27, 2023

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