+0

# row-echolen form

0
114
1

https://prnt.sc/pc1sbm

a bit confused

Sep 28, 2019

#1
+11097
+2

1      2      1            5

2    - 1     2          15

3      1   – 1            8

The diagonal field of the 1st line is already 1.

With the 1st row, all other rows in the 1st column are set to 0.

To the 2nd row the -2-fold of the 1st row is added:

1      2      1          5

0    - 5      0          5

3      1    - 1          8

The -3-fold of the 1st line is added to the 3rd line:

1       2       1          5

0     - 5      0          5

0     - 5    - 4       - 7

By dividing the 2nd line by -5 the diagonal element is made to 1:

1     2     1       5

0     1     0     - 1

0   - 5  - 4     - 7

With the 2nd row, all other rows in the 2nd column are set to 0.

The 2nd line is added to the 1st line by a factor of -2:

1     0     1       7

0    1      0    - 1

0  - 5   - 4    - 7

The 5-fold of the 2nd line is added to the 3rd line:

1     0     1        7

0     1     0      - 1

0     0   - 4     - 12

By dividing the 3rd line by -4 the diagonal element is made to 1:

1     0     1        7

0     1     0      - 1

0     0     1        3

With the 3rd row, all other rows in the 3rd column are set to 0.

To the 1st line the -1x of the 3rd line is added:

1     0     0       4

0     1     0     - 1

0     0     1       3

The last column contains the solutions.

Sep 28, 2019

#1
+11097
+2

1      2      1            5

2    - 1     2          15

3      1   – 1            8

The diagonal field of the 1st line is already 1.

With the 1st row, all other rows in the 1st column are set to 0.

To the 2nd row the -2-fold of the 1st row is added:

1      2      1          5

0    - 5      0          5

3      1    - 1          8

The -3-fold of the 1st line is added to the 3rd line:

1       2       1          5

0     - 5      0          5

0     - 5    - 4       - 7

By dividing the 2nd line by -5 the diagonal element is made to 1:

1     2     1       5

0     1     0     - 1

0   - 5  - 4     - 7

With the 2nd row, all other rows in the 2nd column are set to 0.

The 2nd line is added to the 1st line by a factor of -2:

1     0     1       7

0    1      0    - 1

0  - 5   - 4    - 7

The 5-fold of the 2nd line is added to the 3rd line:

1     0     1        7

0     1     0      - 1

0     0   - 4     - 12

By dividing the 3rd line by -4 the diagonal element is made to 1:

1     0     1        7

0     1     0      - 1

0     0     1        3

With the 3rd row, all other rows in the 3rd column are set to 0.

To the 1st line the -1x of the 3rd line is added:

1     0     0       4

0     1     0     - 1

0     0     1       3

The last column contains the solutions.

Omi67 Sep 28, 2019