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Hank can row a boat 1 mi upstream (against the current) in 24 min. He can row the same distance downstream in 13 min. If both the rowing speed and current speed are constant, find Hanks rowing speed and the apes of the current. 

 Aug 30, 2016
 #1
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Let  H  =  rate of Hank in still water.

Let  C  =  rate of the current.

 

The rate downstream is:  H + C

The rate upstream is:       H - C

 

               Distance  =  rate x time

downstream:      1  =  (H + C) · 13      --->      1  =  13H + 13C     --->  x 24  --->     24  =  312H + 312C

upstream:           1  =  (H - C) · 24      --->      1  =  24H - 24C     --->  x 13   --->     13  =  312H - 312C

Adding down the columns:                                                                                       37  =  624H     --->     H  =  37/624                        

                                24  =  312H + 312C                    --->      24  =   312H + 312C

                                13  =  312H - 312C     --->  x -1  --->     -13  =  -312H + 313C 

Adding down the columns:                                                      11  =                624C     --->     C  =  11/624

 

Both of the rates are in terms of miles per minute.

 Aug 31, 2016
 #2
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Hank's speed upstream =1/(24/60)=2.5 mph
Hank's speed downstream=1/(13/60) =4 8/13 mph
His average speed back and forth=[2.5 + 4 8/13]=(7 3/26) / 2 =3 29/52 mph.
The speed of the current =[4 8/13 - 2.5] / 2 =1 3/52 mph.

 Aug 31, 2016

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