a car travels at a velocity of 25m/s^-1 when the engine is turned off. calculate the cars travel before coming to a rest if the deceleration is 1.47m/s^-2
+37084 How many seconds does it go before v= 0?
vf=vo + at
0 = 25 + (-1.47) t yields t=17 seconds
How FAR does it go in 17 seconds?
xf=xo + vo t + 1/2 at^2 (xo = 0 in this example)
xf= 25(17) + 1/2 (-1.47)(17^2) yields distance = xf = 212.58 meters
