Atomic weight of
N=14
H= 1 x 3 = 3 NH3 = 17 gm /mole
1.2 x 10^3/17 = 70.59 moles
Since the molar mass of NH3 =17.031 g/mol, then:
[1.2 x 10^3] / 17.031 =70.46... moles of NH3.
Just depends on how many digits you want to go:
Atomic weight of
N=14.0067
H= 1.00794 x 3 = 3.02382 NH3 = 17.03052 gm /mole
1.2 x 10^3/17.03052 = 70.46173575 moles
The original weight had only TWO significant digits, so I used 2 significant digits in the atomic weights....LOL