A rock is thrown up with an initial velocity of 15 meters per second. Ignoring energy lost to friction, how high will the rock rise?
\({K}_{initial} = U_{final} \\ {1 \over 2} {mv²} = mgh\\ h = {1 \over 2} {v² \over g}\\ h = {1 \over 2} {15² \over 10} = 11.25 \ meters\)
so 10 would be used as gravity, not 9.8? Also, are m, v, and h all the regular variables for their respective objects?
You can use whatever you want for gravity, 10 or 9.8 or 9.81
I'm not sure if I understand your question, m is the mass of the object, v is its velocity and h is what you want to find.
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