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Two 3.1 kg physical science textbooks on a bookshelf are 0.26 m apart. What is the magnitude of the gravitational attraction between the books?

 Sep 21, 2015
 #1
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F=9.84 X 10^-9 m/sec^2

 Sep 21, 2015
 #2
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The gravitational attraction is given by \(F=G\frac{m_1m_2}{r^2}\)

 

G = 6.6742*10^-11*m^3/(kg*sec^2)

 

The m's are masses and r is the distance between them.

 

F = 6.6742*10^-11 x (3.1x3.1)/(0.26^2) = 9.49x10^-9 N

 

The units are Newtons - a force (not m/sec^2 which is acceleration)

 Sep 21, 2015

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