sec^(-1)(-3.44)=?

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sec^(-1)(-3.44)=?

Guest Jul 17, 2014

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Best Answer

+118723

+5

$$sec^{-1}(-3.44)
=cos^{-1}(-1/3.44)$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{3.44}}}}\right)} = {\mathtt{106.899\: \!729\: \!383\: \!3^{\circ}}}$$

.

Melody Jul 18, 2014

1⁺⁰ Answers

+118723

+5

Best Answer

$$sec^{-1}(-3.44)
=cos^{-1}(-1/3.44)$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{3.44}}}}\right)} = {\mathtt{106.899\: \!729\: \!383\: \!3^{\circ}}}$$

Melody Jul 18, 2014

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