((sec^2(4))-(tan^2(4))+4tan(4))/(sec(4))

Question

0

758

1

Guest Oct 1, 2014

+23252

+5

Best Answer

Using the Pythagorean indentity: sec²X - tan²X = 1 ---> sec²(4) - tan²(4) = 1

4tan(4) / sec(4) = [ 4·sin(4) / cos(4) ] / (1/cos(4) = [ 4·sin(4) / cos(4) ] x cos(4)

= 4sin(4)

So, this reduces to 1 + 4sin(4)

geno3141 Oct 1, 2014

geno3141 · Answer 1 · 2014-10-01T07:36:01

Using the Pythagorean indentity: sec²X - tan²X = 1 ---> sec²(4) - tan²(4) = 1

4tan(4) / sec(4) = [ 4·sin(4) / cos(4) ] / (1/cos(4) = [ 4·sin(4) / cos(4) ] x cos(4)

= 4sin(4)

So, this reduces to 1 + 4sin(4)