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sec(-46\deg 6'12") find the decimal value

 Feb 23, 2019
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\(12'' = \dfrac{12}{3600}^\circ = \dfrac{1}{300}^\circ\\ 6' = \dfrac{6}{60}^\circ = \dfrac{1}{10}^\circ\\ 6'12'' = \dfrac{31}{300}^\circ = 0.10\bar{3}^\circ\\ -46^\circ6'12'' = -46.10\bar{3}^\circ\\ \sec(46.10\bar{3}) \approx 1.44225\)

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 Feb 23, 2019

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