The common ratio is \({\sqrt{10} \over \sqrt{2}} = \sqrt 5\)
The 7th term will be: \(\sqrt2 \times \sqrt5^6 = \color{brown}\boxed{125 \sqrt 2}\)
The common ratio is \({\sqrt{10} \over \sqrt{2}} = \sqrt 5\)
The 7th term will be: \(\sqrt2 \times \sqrt5^6 = \color{brown}\boxed{125 \sqrt 2}\)