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Define the sequence of positive integers a_n recursively by a_1=3 and a_n=3(a_n-  1) for all n> =2. Determine the last two digits of a_{2007}.

 Dec 11, 2021
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The GP is as follows:

 

3,  9,  27,  81,  243,................a(2007) ==3^2007 mod 10^10 ==9,532,282,187 - these are the last 10 digits of a(2007)

 Dec 12, 2021

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