1.
inf
∑ 2 / [ n ( n + 1) ] converges to 2
1
This series converges by a comparison test to 2 / n^2 [ which conveges by the integral test ]
2 / n^2 2 1/2 2/9 ..........
2 / [ n ( n + 1) ] 1 1/3 1/6 ..........
Both series > 0 for all terms....and, term by term, the second series is smaller than the second
So....if 2/n^2 converges....so does 2 / [ n ( n + 1) ]
2.
inf
∑ [ n / ( n^2 - 1) ]
2
This series diverges by a comparison test to 1 / n [ which diverges by the p - series test]
1/n 1/2 1/3 1/4 .........
n / ( n^2 - 1) 2/3 3/8 4/15 ........
Both series > 0 for all terms....and, term by term, the first series is smaller than the second
So....if 1/n diverges....so does n / ( n^2 - 1)
.
1.
inf
∑ 2 / [ n ( n + 1) ] converges to 2
1
This series converges by a comparison test to 2 / n^2 [ which conveges by the integral test ]
2 / n^2 2 1/2 2/9 ..........
2 / [ n ( n + 1) ] 1 1/3 1/6 ..........
Both series > 0 for all terms....and, term by term, the second series is smaller than the second
So....if 2/n^2 converges....so does 2 / [ n ( n + 1) ]
2.
inf
∑ [ n / ( n^2 - 1) ]
2
This series diverges by a comparison test to 1 / n [ which diverges by the p - series test]
1/n 1/2 1/3 1/4 .........
n / ( n^2 - 1) 2/3 3/8 4/15 ........
Both series > 0 for all terms....and, term by term, the first series is smaller than the second
So....if 1/n diverges....so does n / ( n^2 - 1)
.