Evaluate the infinite geometric series: 2 + 1/8 + 1/128 + ...
The sum is \(a\over{1-r}\)
\(a\) = first term
\(r\) = common ratio
So the sum is... \(2\over{1-{1\over16}}\) = \(\color{brown}\boxed{2 {2\over15}}\)