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Let a1, a2, a3, be an arithmetic sequence. Let Sn denote the sum of the first n terms. If S20=15 and S10=0, then find S70.

 Mar 28, 2024
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0   +  55d  =   1/5

55d = 1/5

d  =   1 / [ 5 * 55]  =  1 / 275

 

70th term is  0  + 60d  =   60 / 275   =12 / 55

 

S70 =   [  12/55 + 0 ] [70 -10 + 1 ]  / 2   =

 

[12/55] * 61  / 2  =   

 

366 / 55

 

 

cool cool cool

 Mar 28, 2024

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