Seven people arrive to dinner, but the circular table only seats six. If two seatings such that one is a rotation of the other are considered the same, then in how many different ways can we choose six people and seat them at the table?
well there is 7 ways to leave someone out so that makes 7 ways to choose 6 people.
there are 5! ways to seat those 6 people.
so maybe 7*5! way.
It is probably wrong. :)