A Kite of area 40 m^2 has one diaganol 2 m longer than the other. Find the length of the diagonals.
Note: Use the formula 1/2*(a*b)or 1/2*(product of diaganols)
Let a be the shorter diagonal, then b = a + 2 and we have:
a(a+ 2)/2 = 40
or: a^2 + 2a - 80 = 0
or: (a + 10)(a - 8) = 0
The only positive solution is a = 8 m, so b = 10 m
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