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Solve for the shapes

 

 Dec 29, 2019
 #1
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"Two red triangles the sum of them is 12, let the red triangle be x, x+x=12, 2x=12, x=6, one red triangle=6) "

"Yellow rectangle and half-shaded triangle, logically I'd give that triangle value of 3 rather than 6. , so let yellow rectangle=f, f-3=1, f=4, yellow rectangle=4

"Green circle added to blue hexagon=17", "Blue hexagon - Green circle =7" hm let's use variables, let the green circle be q and blue hexagon be p" 

q+p=17

p-q=7   system of equations, add both equations,

2p=24

p=12, remember that hexagon is p so hexagon value is 12, substitute, green circle +12=17, green circle=5

 

(Other solution than the system of equations (A logical one rather than mathematical), Notice the pattern that each figure's value number is represented by the number of triangles inside except the circle. I.e. look at the yellow rectangle, draw to diagonals we have 4 triangles, thus it values is 4. half-shaded triangle, only the shaded area so it is half of the full triangle which is 6 if you draw diagonals. 

E.g. the blue hexagon, by drawing it's diagonal you will have 12 triangles and its value is 12.)

 

anyways let's continue, 

So far we have red triangle= 6

Yellow rectangle=4

green circle(q)=5

blue hexagon(p)=12

Thus last line,

6+4+5+uh?=?

well, it is hexagon leaving 2 triangles outside thus its value is 10?(Logical approach)

The mathematical approach would be 4.. as it is a rectangle. 

so

6+4+5+10=25

6+4+5+4=19 

Which one is correct? Check answer..

 Dec 29, 2019
 #2
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*****

 

 

cool cool cool

 Dec 29, 2019
edited by CPhill  Dec 29, 2019

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