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Shawn bought boxes of thank you cards and get well cards. The thank you cards came in boxes of 7 and the get well cards came in boxes of 9. Shawn bought 17 boxes and got a total of 135 cards. How many boxes of each type of card did he buy?

 May 15, 2014

Best Answer 

 #1
avatar+129907 
+5

OK...let's call the number of boxes he bought holding 7 cards, x. And let's call the number of boxes he bought holding 9 cards, y.

So we have

x + y = 17    (A)

And , the number of cards in each box type, times the number it holds added together = 135 

So we have

7x + 9y = 135   and

x +  y   =   17      By multiplying the bottom equation on both sides by -7, we can "eliminate" x. So we have

7x + 9y =    135 

-7x - 7y =  -119    And we get

2y = 16   So

y  = 8      And substituting this into (A), we have

x + 8 = 17   

So x  = 9

So he bought 9 boxes of 7 cards and 8 boxes of 9 cards = 135 cards

 May 15, 2014
 #1
avatar+129907 
+5
Best Answer

OK...let's call the number of boxes he bought holding 7 cards, x. And let's call the number of boxes he bought holding 9 cards, y.

So we have

x + y = 17    (A)

And , the number of cards in each box type, times the number it holds added together = 135 

So we have

7x + 9y = 135   and

x +  y   =   17      By multiplying the bottom equation on both sides by -7, we can "eliminate" x. So we have

7x + 9y =    135 

-7x - 7y =  -119    And we get

2y = 16   So

y  = 8      And substituting this into (A), we have

x + 8 = 17   

So x  = 9

So he bought 9 boxes of 7 cards and 8 boxes of 9 cards = 135 cards

CPhill May 15, 2014
 #2
avatar+2592 
0

That is too much thinking for me Phill lol

 May 15, 2014

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