6(x+4)=3(x-2)
6(x + 4) = 3(x-2) [multiply 6 and 3
6x + 24 = 3x - 6 [subtract 3x, subtract 24
3x = - 30 [divide by 3
x = - 10
\(\begin{array}{rll}6(x+4)&=&3(x-2)\\2(x+4)&=&x-2\color{red}\text{(Divide by 3)}\\ 2x+8&=&x-2\color{red}\text{(Get rid of the brackets)}\\ x+8&=&-2\color{red}\text{(Minus x)}\\ x&=&-10\color{red}\text{(Minus 8)}\end{array} \)