Si el ángulo A es dos veces el ángulo B y este vale π/6, cual es el valor de los ángulos?

If the angle A is twice angle B and this is worth π / 6, which is the value of the angles?

I am unsure as to which angle = π / 6......if it's "A", then "B"  = (1/2)(π / 6) = π / 12  

And the remaining angle = π  - π / 6  - π / 12   =  [ 12π - 2π - π ] / 12   = 9π/12  =  3π/4

If "B"  = π /6, then "A"  = 2(π/6)  = π/3    

And the remaining angle = π - π/6  - π/3  = [ 6π - π - 2π]/ 6   = 3π/6  = π/2

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Estoy seguro de qué ángulo = π / 6 ...... si es "A", luego "B" = (1/2) (π / 6) = π / 12

Y el ángulo restante = π - π / 6 - π / 12 = [12π - 2π - π] / 12 = 9π / 12 = 3π / 4

Si "B" = π / 6, a continuación, "A" = 2 (π / 6) = π / 3

Y el ángulo restante = π - π / 6 - π / 3 = [6π - π - 2π] / 6 = 3π / 6 = π / 2