Let the ordered triples (x,y,z) of complex numbers that satisfy
x+yz=7,y+xz=10,z+xy=10.
be (x1,y1,z1),(x2,y2,z2),…,(xn,yn,zn). Find x1+x2+⋯+xn.
nevermind i got it! the answer is 7 for anyone interested :D
I got 9.