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Let the ordered triples (x,y,z) of complex numbers that satisfy

x+yz=7,y+xz=10,z+xy=10.

be (x1,y1,z1),(x2,y2,z2),,(xn,yn,zn). Find x1+x2++xn.

 Sep 14, 2022
 #1
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nevermind i got it! the answer is 7 for anyone interested :D

 Sep 14, 2022
 #2
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I got 9.

 Sep 15, 2022

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