use sigma notation to write the sum. 4,7,10,13,16
\(\sum_{n=0}^{4}[4 + 3n]=50\)
\(\begin{array}{|rcll|} \hline \sum \limits_{n=1}^{5} 4+(n-1)\cdot 3 = \sum \limits_{n=1}^{5} 1+3n \\ \hline \end{array} \)
