Compute
SOLVED!
∑1000n=11n2+n.
1n2+n=1n(n+1)=An+Bn+1 A+B=0, A=1, B=−1 1n2+n=1n−1n+1
1000∑n=1 (1n−1n+1)= (1−12)+(12−13)+(13−14)+⋯+(11000−11001)= 1−11001=10001001
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